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60=x^2+6x-135
We move all terms to the left:
60-(x^2+6x-135)=0
We get rid of parentheses
-x^2-6x+135+60=0
We add all the numbers together, and all the variables
-1x^2-6x+195=0
a = -1; b = -6; c = +195;
Δ = b2-4ac
Δ = -62-4·(-1)·195
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{51}}{2*-1}=\frac{6-4\sqrt{51}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{51}}{2*-1}=\frac{6+4\sqrt{51}}{-2} $
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